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pish:2.30 GBSCSI:2023/04/16
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Preguntas de conocimiento:Complete la siguiente tabla:Dibujo dela figuraSumadeángulosinternosCálculodelnúmerodediagonalesPerímetro ÁreaCuadriláteroPentágonoHexágonoEneágonoEndecágonoDodecágonoIcoságono2A. Sombreada = 0,3861 𝑐𝑚2Si 𝑎 =54A. Triangulo = b x h= 1,25cm x 0,625cm= 0,781cm= 0,3906 cmSi 𝑎 =54P. Rectángulo = L + L + L + L= 3,75 cmSi 𝑎 =𝑥2 2(Donde 𝑥 es el último dígito desu ID, diferente de cero)A. Triangulo = 4 x 2= 4 cm x 2 cm= 8 cm= 4 cmSi 𝑎 =𝑥2(Donde 𝑥 es el último dígito desu ID, diferente de cero)P. Rectángulo = L + L + L + L= 12 cmSi 𝐴 equivale al área delpolígono regular y 𝑥 Es elvalor de los dos últimosdígitos de su código(diferentes de 0).x= 98A. Cuadrado = 98Lado del cuadrado= √= 9,8995 cmA. Polígono= P x ap.= 98,95 x 9,= 108,84 cmSi 𝐴 equivale al área delpolígono regular y 𝑥 Es elvalor de los dos últimosdígitos de su código(diferentes de 0).P. Polígono= L + L + L + L + L= 98 ,95 cmSi 𝐴 equivale al área delpolígono regular y 𝑥 Es bxh wap elvalor de los dos últimosdígitos de su celular(diferentes de 0).x= 81A. Cuadrado = 81Lado del cuadrado= √= 9 cmA. Polígono= P x ap.= 90 x 9=810 cmSi 𝐴 equivale al área delpolígono regular y 𝑥 Es elvalor de los dos últimosdígitos de su celular(diferentes de 0).P. Polígono= L + L + L + L + L= 90 cmCalculamos el volumen:233Luego la capacidad de la pirámide en Litros suponemos que el litro es agua para usar la conversión:3Entonces 𝑣 = 16 𝑚31000 𝐿1 𝑚3La capacidad del tanque en forma de pirámide es de 16000 L.ConoDatos:bxh wapCalculamos el radio:Calculamos el volumen:222233Luego la capacidad del cono en Litros suponemos que el litro es agua para usar la conversión:3Entonces 𝑣 = 9 , 4248 𝑚31000 𝐿1 𝑚3La capacidad del tanque en forma de Cono es de 9424,8 L.CilindroDatos:Calculamos el radio:22Calculamos el volumen:333333Luego la capacidad del Esférico en Litros suponemos que el litro es agua para usar la conversión:3Entonces 𝑣 = 14 , 137 𝑚31000 𝐿1 𝑚3La capacidad del tanque en forma de Esfera es de 14137L.Para convertir nuevamente de L a ml utilizamos la relación:LuegoPirámide = 𝑣𝑝 = 16000 𝐿 ∗1000……
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